/*
[The "BSD licence"]
Copyright (c) 2005-2008 Terence Parr
All rights reserved.

Redistribution and use in source and binary forms, with or without
modification, are permitted provided that the following conditions
are met:
1. Redistributions of source code must retain the above copyright
notice, this list of conditions and the following disclaimer.
2. Redistributions in binary form must reproduce the above copyright
notice, this list of conditions and the following disclaimer in the
documentation and/or other materials provided with the distribution.
3. The name of the author may not be used to endorse or promote products
derived from this software without specific prior written permission.

THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR
IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES
OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED.
IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT,
INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT
NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
(INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
*/
package org.antlr.runtime.tree;

import org.antlr.runtime.IntStream;
import org.antlr.runtime.TokenStream;

/** A stream of tree nodes, accessing nodes from a tree of some kind */
public interface TreeNodeStream extends IntStream {
	/** Get a tree node at an absolute index i; 0..n-1.
	 *  If you don't want to buffer up nodes, then this method makes no
	 *  sense for you.
	 */
	public Object get(int i);

	/** Get tree node at current input pointer + i ahead where i=1 is next node.
	 *  i<0 indicates nodes in the past.  So LT(-1) is previous node, but
	 *  implementations are not required to provide results for k < -1.
	 *  LT(0) is undefined.  For i>=n, return null.
	 *  Return null for LT(0) and any index that results in an absolute address
	 *  that is negative.
	 *
	 *  This is analogus to the LT() method of the TokenStream, but this
	 *  returns a tree node instead of a token.  Makes code gen identical
	 *  for both parser and tree grammars. :)
	 */
	public Object LT(int k);

	/** Where is this stream pulling nodes from?  This is not the name, but
	 *  the object that provides node objects.
	 */
	public Object getTreeSource();

	/** If the tree associated with this stream was created from a TokenStream,
	 *  you can specify it here.  Used to do rule $text attribute in tree
	 *  parser.  Optional unless you use tree parser rule text attribute
	 *  or output=template and rewrite=true options.
	 */
	public TokenStream getTokenStream();

	/** What adaptor can tell me how to interpret/navigate nodes and
	 *  trees.  E.g., get text of a node.
	 */
	public TreeAdaptor getTreeAdaptor();

	/** As we flatten the tree, we use UP, DOWN nodes to represent
	 *  the tree structure.  When debugging we need unique nodes
	 *  so we have to instantiate new ones.  When doing normal tree
	 *  parsing, it's slow and a waste of memory to create unique
	 *  navigation nodes.  Default should be false;
	 */
	public void setUniqueNavigationNodes(boolean uniqueNavigationNodes);

    /** Reset the tree node stream in such a way that it acts like
     *  a freshly constructed stream.
     */
    public void reset();

	/** Return the text of all nodes from start to stop, inclusive.
	 *  If the stream does not buffer all the nodes then it can still
	 *  walk recursively from start until stop.  You can always return
	 *  null or "" too, but users should not access $ruleLabel.text in
	 *  an action of course in that case.
	 */
	public String toString(Object start, Object stop);


	// REWRITING TREES (used by tree parser)

	/** Replace from start to stop child index of parent with t, which might
	 *  be a list.  Number of children may be different
	 *  after this call.  The stream is notified because it is walking the
	 *  tree and might need to know you are monkeying with the underlying
	 *  tree.  Also, it might be able to modify the node stream to avoid
	 *  restreaming for future phases.
	 *
	 *  If parent is null, don't do anything; must be at root of overall tree.
	 *  Can't replace whatever points to the parent externally.  Do nothing.
	 */
	public void replaceChildren(Object parent, int startChildIndex, int stopChildIndex, Object t);
}
